I person been moving connected longitudinal tyre exemplary for a while and perpetually brushwood problems pinch nan formulation of rolling resistance. Consider 1 instrumentality exemplary coming down from a damp. It is simply a 2DOF strategy (V and omega). The FBD of nan problem is arsenic such:

Defining +x on down nan damp leads to Newton's equation: m * g * sin(beta)-F_c=m*V_dot.

Defining +omega on down nan damp leads to equation: F_c * R=J * omega_dot.

Define F_c: m * g * mu_k * cos(beta).

Above equations create specified a situation: The wide starts rolling and ever accelerates, which is not physically meaningful. After a while it should spell astatine changeless speed.

To do so, I adhd rolling guidance arsenic Pajeska's suggestion:

F_r = (q_0 + q_1*abs(V/Vc) + q_2(V/Vc)^4) * N

Adding rolling guidance arsenic above, I get this situation: The wide starts rolling pinch mini gaffe arsenic expected, past it reaches its maximum linear speed; however, it starts spinning! For, I selected **application constituent of rolling guidance arsenic interaction point**, **which is again Pajeska's suggestion**.

So my questions are:

- what should beryllium nan exertion constituent of rolling guidance and why?
- does angular velocity (omega) impact rolling resistance?
- what will beryllium guidance of rolling resistance, inverse of V aliases omega?